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Find the amount at the end of 12 years of an annuity of ₹ 5,000 payable at the beginning of each year, if the money is compounded at 10% per annum. [(1.1)12 = 3.1384]

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प्रश्न

Find the amount at the end of 12 years of an annuity of ₹ 5,000 payable at the beginning of each year, if the money is compounded at 10% per annum. [(1.1)12 = 3.1384]

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उत्तर

Here a = 5000, i = 10% = `10/100` = 0.1, n = 12

Amount A = `(1 + "i") "a"/"i" [(1 + "i")^"n" - 1]`

= `(1 + 0.1) 5000/(10/100) [(1 + 0.1)^12 - 1]`

= (1.1) 50000 [(1.1)12 – 1]

= 55000 [3.1384 – 1]

= 55000 [2.1384]

= ₹ 1,17,612

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पाठ 7: Financial Mathematics - Exercise 7.1 [पृष्ठ १६७]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 7 Financial Mathematics
Exercise 7.1 | Q 8 | पृष्ठ १६७

संबंधित प्रश्‍न

Find the amount of an ordinary annuity of ₹ 3,200 per annum for 12 years at the rate of interest of 10% per year. [(1.1)12 = 3.1384]


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Find the amount of an ordinary annuity of 12 monthly payments of ₹ 1,500 that earns interest at 12% per annum compounded monthly. [(1.01)12 = 1.1262]


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₹ 5000 is paid as perpetual annuity every year and the rate of C.I. 10%. Then present value P of immediate annuity is __________.


If ‘a’ is the annual payment, ‘n’ is the number of periods and ‘i’ is compound interest for ₹ 1 then future amount of the ordinary annuity is


Example of contingent annuity is ___________.


Find the amount of annuity of ₹ 2000 payable at the end of each year for 4 years of money is worth 10% compounded annually. [(1.1)4 = 1.4641]


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Find the amount of an ordinary annuity of ₹ 600 is made at the end of every quarter for 10 years at the rate of 4% per year compounded quarterly. [(1.01)40 = 1.4889]


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