Question

Find the 37th term of the AP `6, 7 3/4, 9 1/2, 11 1/4,`....

Answer 1

The given AP is `6, 7 3/4, 9 1/2, 11 1/4,`....

First term, a = 6 and common difference, d = `7 3/4 - 6`

⇒ `31/4 - 6`

⇒ `(31 - 24)/4 = 7/4`

Now, T₃₇ = a + (37 – 1)d

= a + 36d

= `6 + 36 xx 7/4`

= 6 + 63

= 69

 ∴ 37^th term = 69