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प्रश्न
Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2
बेरीज
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उत्तर
t8 = 768
= ar7
r = 2
t10 = ar9
= ar7 × r × r
= 768 × 2 × 2
= 3072
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