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प्रश्न
Find the sum invested at `12 1/2` p.a. compound interest on which the interest for the third year exceeds that of the first year by Rs 531.25.
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उत्तर
Let the sum be P
Interest for first year:
`"P" (1 + 25/(2 xx 100)) - "P"` ..................(i)
Interest for third year:
`"P" (1 + 25/(2 xx 100))^3 - "P" (1 + 25/(2 xx 100))^2` .........(ii)
Subtracting (ii) from (i)
`"P" (1 + 25/(2 xx 100))^3 - "P" (1 + 25/(2 xx 100))^2 - "P" (1 + 25/(2 xx 100)) + "P"` = Rs 531.25
Rs 531. 25 = 1. 423828 P - 1. 265625 P - 1. 125 P + P
Rs 531. 25 = 0. 033203 P
P = Rs 16,000
Hence the sum is Rs 16,000
संबंधित प्रश्न
On what sum of money will the difference between the compound interest and simple interest for 2 years be equal to Rs. 25 if the rate of interest charged for both is 5% p.a.?
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| Year ↓ |
Initial amount (Rs.) |
Interest (Rs.) |
Final amount (Rs.) |
| 1st | 16,000 | 800 | 16,800 |
| 2nd | ........... | ........... | ........... |
| 3rd | ........... | ........... | ........... |
| 4th | ........... | ........... | ........... |
| 5th | ........... | ........... | ........... |
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