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प्रश्न
Find the sum of the first n terms of the series: 3 + 7 + 13 + 21 + 31 + …
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उत्तर
The given series is 3 + 7 + 13 + 21 + 31 + …
S = 3 + 7 + 13 + 21 + 31 + …+ an–1 + an
S = 3 + 7 + 13 + 21 + …. + an – 2 + an – 1 + an
On subtracting both the equations, we obtain
S – S = [3 + (7 + 13 + 21 + 31 + …+ an–1 + an)] – [(3 + 7 + 13 + 21 + 31 + …+ an–1) + an]
S – S = 3 + [(7 – 3) + (13 – 7) + (21 – 13) + … + (an – an–1)] – an
0 = 3 + [4 + 6 + 8 + … (n –1) terms] – an
an = 3 + [4 + 6 + 8 + … (n –1) terms]


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