मराठी

Find sin θ, cos θ and tan (90° - θ). - Mathematics

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प्रश्न

Find sin θ, cos θ and tan (90° - θ).

बेरीज
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उत्तर

Given:

BC = 30 units (base)

AC = 34 units (hypotenuse)

∠B = 90°

∠C = θ

Step 1: Find the height (AB)

Using the Pythagoras Theorem:

AB2 = AC2 − BC2

= 342 − 302

= 1156 900 = 256

⇒ AB = `sqrt256` = 16

AB = 16 (opposite to θ)

BC = 30 (opposite to θ)

AC = 34 (hypotenuse)

Step 2: Find the trigonometric values

sin θ = opposite ÷ hypotenuse

= 16 ÷ 34 = `8/17`

cos θ = adjacent ÷ hypotenuse

= 30 ÷ 34 = `15/17`

tan(90° - θ) = cot(θ) = adjacent ÷ opposite

= 30 ÷ 16 = `15/8`

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पाठ 19: Trigonometry - EXERCISE 19A [पृष्ठ २३१]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 19 Trigonometry
EXERCISE 19A | Q I. 1. | पृष्ठ २३१
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