Advertisements
Advertisements
प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by \[x + \pi\] .
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = x^3 + 3x^2 + 3x + 1`
`j(x) = x+pi`
`⇒ j (x) = x-(-pi),`
We will find the remainder when f(x) is divided by j(x) .
By the remainder theorem, when f(x) is divided by j(x)the remainder is
` = f(- pi)`
`= (- pi) ^3 + 3(-pi)^2 +3(- pi)+1`
` = -pi^3 + 3pi^2 -3pi +1`
APPEARS IN
संबंधित प्रश्न
Find the value of a, if x + 2 is a factor of 4x4 + 2x3 − 3x2 + 8x + 5a.
In the following two polynomials, find the value of a, if x − a is factor x6 − ax5 + x4 − ax3 + 3x − a + 2.
Find the values of a and b so that (x + 1) and (x − 1) are factors of x4 + ax3 − 3x2 + 2x + b.
y3 − 2y2 − 29y − 42
If x + a is a factor of x4 − a2x2 + 3x − 6a, then a =
The value of k for which x − 1 is a factor of 4x3 + 3x2 − 4x + k, is
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
Factorise the following:
x² + 10x + 24
Factorise the following:
a2 + 10a – 600
Factorise the following:
(p – q)2 – 6(p – q) – 16
