Advertisements
Advertisements
प्रश्न
Find the principal value of `sin^-1(1/sqrt2)`
बेरीज
Advertisements
उत्तर
Let `sin^-1(1/sqrt2)`
`∴ sin^-1x=(1/sqrt2)`
`∴ sin x= sin(pi/4)`
The principal value branch of
`sin^-1 "x" "is" [-pi/2,pi/2] `
`sin^-1 (sin theta) = theta`
Hence, the required principal value of x is `pi/4`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
