Advertisements
Advertisements
प्रश्न
Find the median wages for the following frequency distribution:
| Wages per day (in Rs) | 61 – 70 | 71 – 80 | 81 – 90 | 91 – 100 | 101 – 110 | 111 – 120 |
| No. of women workers | 5 | 15 | 20 | 30 | 20 | 8 |
Advertisements
उत्तर
| Class | Frequency (f) | Cumulative Frequency (cf) |
| 60.5 – 70.5 | 5 | 5 |
| 70.5 – 80.5 | 15 | 20 |
| 80.5 – 90.5 | 20 | 40 |
| 90.5 – 100.5 | 30 | 70 |
| 100.5 – 110.5 | 20 | 90 |
| 110.5 – 120.5 | 8 | 98 |
| N = Σ𝑓 = 98 |
Now, N = 98
⇒ `N/2` = 49.
The cumulative frequency just greater than 49 is 70 and the corresponding class is 90.5 – 100.5.
Thus, the median class is 90.5 – 100.5.
Now, l = 90.5, h = 10, f = 30, cf = c.f. of preceding class = 40 and `N/2` = 49.
∴ Median, `M = l + {h×((N/2−f)/f)}`
`= 90.5 + {10 × ((49 − 40)/30)}`
= 90.5 + 3
= 93.5
Hence, median wages = Rs. 93.50.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
