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प्रश्न
Find α and β, if x + 1 and x + 2 are factors of x3 + 3x2 − 2αx + β.
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उत्तर
Let f (x) = x3 + 3x2 − 2αx + β be the given polynomial.
By the factor theorem, (x+1) and (x+2) are the factor of the polynomial f(x) if and f (-2) (f(-1))both are equal to zero.
Therefore,
\[f( - 1) = ( - 1 )^3 + 3( - 1 )^2 - 2\alpha\left( - 1 \right) + \beta = 0\]
\[ \Rightarrow f( - 1) = - 1 + 3 + 2\alpha + \beta = 0\]
\[ \Rightarrow 2\alpha + \beta = - 2 . . . (i)\]
\[f( -2 ) = ( - 2 )^3 + 3( - 2 )^2 - 2\alpha\left( - 2 \right) + \beta = 0\]
\[ - 8 + 12 + 4\alpha + \beta = 0\]
\[ 4\alpha + \beta = - 4 . . . (ii)\]
Subtracting (i) from (ii)
We get,
`(4alpha +beta) - (2alpha + beta) = -2`
`2alpha = -2`
\[\alpha = - 1\]
Putting the value of \[\alpha\]
in equation (i), we get
`2 xx (-1) + beta = -2`
` - 2 + beta = -2`
`beta = 0`
Hence, the value of α and β are −1, 0 respectively.
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