Question

Find the following product:
−11a(3a + 2b)

Answer 1

To find the product, we will use distributive law as follows:

\[- 11a\left( 3a + 2b \right)\]

\[ = \left( - 11a \right) \times 3a + \left( - 11a \right) \times 2b\]

\[ = \left( - 11 \times 3 \right) \times \left( a \times a \right) + \left( - 11 \times 2 \right) \times \left( a \times b \right)\]

\[ = \left( - 33 \right) \times \left( a^{1 + 1} \right) + \left( - 22 \right) \times \left( a \times b \right)\]

\[ = - 33 a^2 - 22ab\]

Thus, the answer is \[- 33 a^2 - 22ab\].