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प्रश्न
Find the equation of the hyperbola whose focus is (2, 2), directrix is x + y = 9 and eccentricity = 2.
थोडक्यात उत्तर
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उत्तर
Let S be the focus and \[P\left( x, y \right)\] be any point on the hyperbola.
Draw PM perpendicular to the directrix.
By definition:
SP = ePM

\[\Rightarrow\] \[\sqrt{(x - 2 )^2 + (y - 2 )^2} = 2\left( \frac{x + y - 9}{\sqrt{2}} \right)\]
Squaring both the sides:
\[(x - 2 )^2 + (y - 2 )^2 = 4 \left( \frac{x + y - 9}{2} \right)^2 \]
\[ \Rightarrow x^2 - 4x + 4 + y^2 - 4y + 4 = 2\left( x^2 + y^2 + 81 + 2xy - 18y - 18x \right)\]
\[ \Rightarrow x^2 - 4x + 4 + y^2 - 4y + 4 = 2 x^2 + 2 y^2 + 162 + 4xy - 36y - 36x\]
\[ \Rightarrow x^2 + y^2 + 4xy - 32y - 32x + 154 = 0\]
∴ Equation of the hyperbola = \[x^2 + y^2 + 4xy - 32y - 32x + 154 = 0\]
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