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प्रश्न
Find each of the following product:
(7ab) × (−5ab2c) × (6abc2)
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उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e.,
\[a^m \times a^n = a^{m + n}\]
We have:
\[\left( 7ab \right) \times \left( - 5a b^2 c \right) \times \left( 6ab c^2 \right)\]
\[ = \left\{ 7 \times \left( - 5 \right) \times 6 \right\} \times \left( a \times a \times a \right) \times \left( b \times b^2 \times b \right) \times \left( c \times c^2 \right)\]
\[ = \left\{ 7 \times \left( - 5 \right) \times 6 \right\} \times \left( a^{1 + 1 + 1} \right) \times \left( b^{1 + 2 + 1} \right) \times \left( c^{1 + 2} \right)\]
\[ = - 210 a^3 b^4 c^3\]
Thus, the answer is \[- 210 a^3 b^4 c^3\] .
संबंधित प्रश्न
Find each of the following product:
\[\frac{1}{4}xy \times \frac{2}{3} x^2 y z^2\]
Find each of the following product: \[\left( \frac{7}{9}a b^2 \right) \times \left( \frac{15}{7}a c^2 b \right) \times \left( - \frac{3}{5} a^2 c \right)\]
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Simplify: a(b − c) + b(c − a) + c(a − b)
Simplify: a2b(a − b2) + ab2(4ab − 2a2) − a3b(1 − 2b)
Multiply:
(3x2 + y2) by (2x2 + 3y2)
Simplify:
(x2 − 3x + 2)(5x − 2) − (3x2 + 4x − 5)(2x − 1)
Simplify:
(x3 − 2x2 + 3x − 4) (x −1) − (2x − 3)(x2 − x + 1)
Solve the following equation.
2(x − 4) = 4x + 2
Solve:
(3x + 2y)(7x − 8y)
