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Find dydxdydx if : x = a cos3θ, y = a sin3θ at θ = π3 - Mathematics and Statistics

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प्रश्न

Find `"dy"/"dx"` if : x = a cos3θ, y = a sin3θ at θ = `pi/(3)`

बेरीज
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उत्तर

a cos3θ, y = a sin3θ
Differentiating x and y w.r.t. θ, we get
`"dx"/"dθ" = a"d"/"dθ"(cosθ)^3`

= `a xx 3cos^2θ."d"/"dθ"(cosθ)`
= 3a cos2θ(– sinθ)
= – 3a cos2θ sinθ
and
`"dy"/"dθ" = a"d"/"dθ"(sinθ)^3`

= `a xx 3 sin^2θ."d"/"dθ"(sinθ)`
= 3a sin2θ cosθ
∴`"dy"/"dx" = (("dy"/"dθ"))/(("dx"/"dθ")`

= `(3a sin^2θ cosθ)/(-3a cos^2θ sinθ)`

= – tanθ

∴ `(dx/dy)_("at"  θ - pi/3)`

= `-tan  pi/(3)`
= `-sqrt(3)`   

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पाठ 1: Differentiation - Exercise 1.4 [पृष्ठ ४८]

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