Advertisements
Advertisements
प्रश्न
`" Find the distance between the points" A ((-8)/5,2) and B (2/5,2)`
Advertisements
उत्तर
The given points are ` A ((-8)/5,2) and B (2/5,2)`
Then ` (x_1 = (-8)/5 , y_1 =2 ) and ( x_2 = 2/5 , y_2 = 2)`
Therefore ,
`AB = sqrt((x_2 -x_1)^2 +(y_2-y_1)^2)`
`= sqrt({2/5-((-8)/5)}^2 +(2-2)^2)`
`= sqrt((2)^2 +(0)^2`
`=sqrt(4+0)`
`= sqrt(4)`
= 2 units .
APPEARS IN
संबंधित प्रश्न
If A(4, 3), B(-1, y) and C(3, 4) are the vertices of a right triangle ABC, right-angled at A, then find the value of y.
If P (2, – 1), Q(3, 4), R(–2, 3) and S(–3, –2) be four points in a plane, show that PQRS is a rhombus but not a square. Find the area of the rhombus
Find the distance between the following pair of points:
(asinα, −bcosα) and (−acos α, bsin α)
Find all possible values of y for which distance between the points is 10 units.
Show that the points A(1, 2), B(1, 6), C(1 + 2`sqrt3`, 4) are vertices of an equilateral triangle.
Find the distances between the following point.
P(–6, –3), Q(–1, 9)
Find the distance between the following pairs of point in the coordinate plane :
(7 , -7) and (2 , 5)
Find the distance of the following point from the origin :
(5 , 12)
Find the distance of the following point from the origin :
(0 , 11)
Find the distance of a point (13 , -9) from another point on the line y = 0 whose abscissa is 1.
Find the distance between the origin and the point:
(-8, 6)
Show that the points (2, 0), (– 2, 0) and (0, 2) are vertices of a triangle. State the type of triangle with reason
The point which divides the lines segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the ______.
The distance between the points A(0, 6) and B(0, –2) is ______.
The points (– 4, 0), (4, 0), (0, 3) are the vertices of a ______.
A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.
What type of a quadrilateral do the points A(2, –2), B(7, 3), C(11, –1) and D(6, –6) taken in that order, form?
Find distance between points P(– 5, – 7) and Q(0, 3).
By distance formula,
PQ = `sqrt(square + (y_2 - y_1)^2`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(125)`
= `5sqrt(5)`
Find the distance between the points O(0, 0) and P(3, 4).
The distance between the points (0, 5) and (–3, 1) is ______.
