Question

Find the cube of \[\frac{12}{7}\] .

 

 

Answer 1

\[\because\]  \[\left( \frac{m}{n} \right)^3 = \frac{m^3}{n^3}\] 

\[\therefore\] \[\left( \frac{12}{7} \right)^3 = \frac{{12}^3}{7^3} = \frac{12 \times 12 \times 12}{7 \times 7 \times 7} = \frac{1728}{343}\]