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प्रश्न
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
बेरीज
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उत्तर

let o (x, y) be the centre of the circle.
OA = OB (radii of square circle)
⇒ OA2 = OB2
(x + 2)2 + (y + 3)2 = (x + 1)2 + (y - 0)2
⇒ x2 + 4 + 4x + y2 + 9 + 6y = x2 + 1 + 2x + y2
⇒ 2x + 6y + 12 = 0
⇒ x + 3y + 6 = 0 .........(1)
Similarly, OB=OC
⇒ OB2 =OC2
(x + 1)2 + (y + 0)2 = (x + 7)2 + (y - 6)2
⇒ x2 + 1 + 2x + y2 = x2 + 49 - 14x + y2 + 36 +12y
⇒ 16x - 12y - 84 = 0
⇒ 4x - 3y - 21 = 0 .... (2)
⇒ 4x + 12y +24 = 0 .....(1)
on solving (1)& (2) we get,
- 15 y - 45 = 0
⇒ y = -3
from (1)
x - 9 + 6 = 0
⇒ x = 3
Thus coordinate of O are (3 , -3)
Radius =`sqrt ((3 + 2)^2 + (- 3 + 3)^2)`
`= sqrt (25 + 0)`
` = sqrt 25` units
= 5 units
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