Advertisements
Advertisements
प्रश्न
Find the area of an equilateral triangle having altitude h cm.
Advertisements
उत्तर
Altitude of a equilateral triangle, having side a is given by
Altitude = `sqrt(3)/2 a`
Substituting the given value of altitude h cm, we get
`h = sqrt(3)/2 a`
`a = 2/sqrt( 3) h cm `
Area of a equilateral triangle, say A having each side a cm is given by
`A= sqrt(3)/4 a^2`
Area of the given equilateral triangle having each equal side equal to `2/sqrt(3) h cm ` is given by;
`A = sqrt(3)/4 ( 2/sqrt(3) h cm )^2`
`A = sqrt(3)/4 xx 4/3 h^2`
`A = h^2/sqrt(3)cm ^2`
APPEARS IN
संबंधित प्रश्न
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
Radha made a picture of an aeroplane with coloured papers as shown in the given figure. Find the total area of the paper used.

Area of PQRS = Area of PQR + Area of ΔPQS = (6+9.166)𝑐𝑚2=15.166𝑐𝑚2
Find the area of a quadrilateral ABCD in which AD = 24 cm, ∠BAD = 90° and BCD forms an equilateral triangle whose each side is equal to 26 cm. (Take √3 = 1.73)
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is ______.
The adjacent sides of a parallelogram measures 34 m, 20 m and the measure of the diagonal is 42 m. Find the area of parallelogram
The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is ______.
The length of each side of an equilateral triangle having an area of `9sqrt(3)`cm2 is ______.
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per cm2 is ______.
