Advertisements
Advertisements
рдкреНрд░рд╢реНрди
Find the angle subtended at the centre of circle of radius 5cm by an arc of length `((5pi)/3)` cm
Advertisements
рдЙрддреНрддрд░
Radius (r) = 5 cm

ЁЭЬГ = angle subtended at centre (degrees)
Length of Arc =`theta/360^@`× 2ЁЭЬЛr cm
But arc length =`5pi/3`ЁЭСРЁЭСЪ
`theta/360^@× 2pi × 5 =(5pi)/3`
`theta=(360^@×pi)/(3×2pi)= 60^@`
∴ Angle subtended at centre = 60°
shaalaa.com
рдпрд╛ рдкреНрд░рд╢реНрдирд╛рдд рдХрд┐рдВрд╡рд╛ рдЙрддреНрддрд░рд╛рдд рдХрд╛рд╣реА рддреНрд░реБрдЯреА рдЖрд╣реЗ рдХрд╛?
