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प्रश्न
Find the angle between the two lines `2x = 3y = -z and 6x =-y = -4z`
बेरीज
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उत्तर
2x = 3y = -z
`x/3 = y/2 = Z/-6`
and 6x = -y = -4z
`cos theta = |(a_1a_2 + b_1b_2 + c_1c_2)/sqrt(a_1^2 + b_ )|`
= `|(3(4)+2(-24)+ (-6)-6)/(sqrt((3^2+ 2^2+6^2)) .sqrt((4^2 +24^2 + 6^2 )))|`
`=|(12-48+36)/(sqrt(9+4+36).sqrt(16+576+36)) |`
= 0
`theta =90°`
Angle between the two lines 2x = 3y = -z and 6x = -y =-74z is 90°.
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