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प्रश्न
Find AD, if:
बेरीज
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उत्तर
In ΔBCA
∠ABC = ∠BAC = x
∠ACD = ∠BAC + ∠ABC ...[Exterior angle equal to two int. opp. angle]
60° = x + x
60° = 2x
x = 30°
In ΔADB
sin B = `("AD")/("AB")`
sin 30° = `("AD")/(100)`
`(1)/(2) = ("AD")/(100)`
AD = 50 m
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Solution of Right Triangles
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