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प्रश्न
Find acute angles A and B, if `sin (A + 2B) = sqrt(3)/2` and cos(A + 4B) = 0, A > B.
बेरीज
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उत्तर
Sin (A + 2B) = sin 60°
cos (A + 4B) = cos 90°
A + 2B = 60° …(i)
A + 4B = 90° …(ii)
Subtracting (ii) from (i)
A + 4B = 90°
`(-A - 2B = -60)/(2B = 30°)` ∴ B = 15°
A + 4B = 90°
4B = 4(15°) = 4B = 60°
∴ A + 60° = 90° ∴ A = 30°
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