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प्रश्न
Fill in the blanks:
y = ex .tan x
Differentiating w.r.t.x
`("d"y)/("d"x) = "d"/("d"x)("e"^x tan x)`
= `square "d"/("d"x) tanx + tan x "d"/("d"x) square`
= `square square + tan x square`
= `"e"^x [square + square]`
रिकाम्या जागा भरा
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उत्तर
y = ex .tan x
Differentiating w.r.t.x
`("d"y)/("d"x) = "d"/("d"x)("e"^x tan x)`
= `"e"^x "d"/("d"x) tanx + tan x "d"/("d"x) "e"^x`
= `"e"^x sec^2x + tan x "e"^x`
= `"e"^x [sec^2x + tan x]`
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