Question

Figure shows two forces acting at points A and B of a rod pivoted at a point O, such that OА = 2 m and OB = 4 m.

The moment of force F₁ about O is:

पर्याय

• 10 Nm (anticlockwise)

• 10 Nm (clockwise)

• 20 Nm (clockwise)

• 20 Nm (clockwise)

Answer 1

10 Nm (clockwise)

Explanation:

Given: F₁ ​= 5 N

OA = 2 m

Moment of couple = Force × perpendicular distance

= 5 × 2

= 10 N m

∴ The force at A tends to rotate the rod anticlockwise.