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प्रश्न
Factorize each of the following quadratic polynomials by using the method of completing the square:
p2 + 6p + 8
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उत्तर
\[p^2 + 6p + 8\]
\[ = p^2 + 6p + \left( \frac{6}{2} \right)^2 - \left( \frac{6}{2} \right)^2 + 8 [\text{ Adding and subtracting }\left( \frac{6}{2} \right)^2 , \text{ that is }, 3^2 ]\]
\[ = p^2 + 6p + 3^2 - 3^2 + 8\]
\[ = p^2 + 2 \times p \times 3 + 3^2 - 9 + 8\]
\[ = p^2 + 2 \times p \times 3 + 3^2 - 1\]
\[ = (p + 3 )^2 - 1^2 [\text{ Completing the square }]\]
\[ = [(p + 3) - 1][(p + 3) + 1]\]
\[ = (p + 3 - 1)(p + 3 + 1)\]
\[ = (p + 2)(p + 4)\]
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A contractor uses the expression 4x2 + 11x + 6 to determine the amount of wire to order when wiring a house. If the expression comes from multiplying the number of rooms times the number of outlets and he knows the number of rooms to be (x + 2), find the number of outlets in terms of ’x’. [Hint : factorise 4x2 + 11x + 6]
