Advertisements
Advertisements
प्रश्न
Factorize `5sqrt5x^2 + 20x + 3sqrt5`
Advertisements
उत्तर
Splitting the middle term,
`= 5sqrt5x^2 + 15x + 5x + 3sqrt5` `[∵ 20 = 15 + 5 and 15 xx 5 = 5 = 5sqrt5 xx 3sqrt5]`
`= 5x(sqrt5x + 3) + sqrt5(sqrt5x + 3)`
`=(sqrt5x + 3)(5x + sqrt5)`
`∴ 5sqrt5 x^2 + 20x + 3sqrt5 = (sqrt5x + 3)(5x + sqrt5)`
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Number 5 added to three times the product of numbers m and n.
Factorize `x^2 + 5sqrt5x + 30`
Factorize `x^2 + 2sqrt3x - 24`
Factorize the following expressions:
y3 +125
`2sqrt2a^3 + 16sqrt2b^3 + c^3 - 12abc`
If x2 + y2 = 29 and xy = 2, find the value of x4 + y4 .
Multiply: (xy + 2b)(xy - 2b)
Divide: 8x + 24 by 4
If x = 2 and y = 3, then find the value of the following expressions
4y – x
A student wrote an algebraic expression for “5 less than a number n divided by 3” as `n/3 - 5`. What error did the student make?
