Advertisements
Advertisements
प्रश्न
Factorise : x4 + x2 + 1
बेरीज
Advertisements
उत्तर
x4 + x2 + 1
= (x2)2 + 2x2. 1 + (1)2 - x2
= ( x2 + 1 )2 - (x)2 [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( x2 + 1 - x )( x2 + 1 + x )
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise : a4 - 1
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : 4xy - x2 - 4y2 + z2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise : 4x4 - x2 - 12x - 36
Factorise : a2 ( b + c) - (b + c)3
Factorise the following by the difference of two squares:
(x + y)2 -1
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
25(x - y)2 - 49(c - d)2
