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प्रश्न
Factorise the following:
`x^2 + 7/6 x - 5/6`
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उत्तर
Given expression: `x^2 + 7/6 x - 5/6`
Step-wise calculation:
Step 1: Clear the fractions by multiplying through by 6 to make factorisation easier:
`6 xx (x^2 + 7/6x - 5/6) = 6x^2 + 7x - 5`
Step 2: Factorise the quadratic 6x2 + 7x – 5.
We look for two numbers whose product is 6 × (–5) = –30 and whose sum is 7.
Those numbers are 10 and –3 since 10 × –3 = –30 and 10 + (–3) = 7.
Step 3: Rewrite the middle term 7x as 10x – 3x:
6x2 + 10x – 3x – 5
Step 4: Group terms:
(6x2 + 10x) – (3x + 5)
Step 5: Factor each group:
2x(3x + 5) – 1(3x + 5)
Step 6: Factor out the common binomial factor:
(3x + 5)(2x – 1)
Step 7: Since we multiplied the original expression by 6, to factorise the original expression, put the factor `1/6` back:
\[ x^2 + \frac{7}{6}x - \frac{5}{6} = \frac{1}{6}(3x + 5)(2x - 1) \]
