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प्रश्न
Factorise the following expression.
`9"x"^2-1/16"y"^2`
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उत्तर
`9x^2-1/16y^2`
Let us recognize it as the difference of the squares of a and b.
a = 9x2 = (3x)2
b = `1/16y^2` = `(1/4y)^2`
a2 − b2 = (a + b) (a − b)
∴ `(3x)^2-(1/4y)^2` = `(3x+1/4y)(3x-1/4y)`
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Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
