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प्रश्न
Factorise the following expression.
`9"x"^2-1/16"y"^2`
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उत्तर
`9x^2-1/16y^2`
Let us recognize it as the difference of the squares of a and b.
a = 9x2 = (3x)2
b = `1/16y^2` = `(1/4y)^2`
a2 − b2 = (a + b) (a − b)
∴ `(3x)^2-(1/4y)^2` = `(3x+1/4y)(3x-1/4y)`
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