Advertisements
Advertisements
प्रश्न
Factorise the following by the difference of two squares:
16a4 - 81b4
बेरीज
Advertisements
उत्तर
16a4 - 81b4
= (4a2)2 - (9b2)2
= (4a2 - 9b2)(4a2 + 9b2)
= [(2a)2 - (3b)2](4a2 + 9b2)
= [(2a - 3b)(2a + 3b)](4a2+ 9b2)
= (2a - 3b)(2a + 3b)(4a2 + 9b2).
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - (2a + 3b)2
Factorise : a2 - 81 (b-c)2
Factorise : 4a2b - 9b3
Factorise : 4a2 - 49b2 + 2a - 7b
Factorise : 9a2 + 3a - 8b - 64b2
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
(x + y)2 -1
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
