Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
बेरीज
Advertisements
उत्तर
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
= (2a + b + 3c - d) + [(2a + b)3 + (2a + b)2(3c - d)]
= 1(2a + b + 3c - d) + (2a + b)2(2a + b + 3c - d)
= (2a + b + 3c - d)[1 + (2a + b)2].
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Factorise by the grouping method : a (a -4) - a + 4
Factorise : 2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
factorise: x2 + 5xy + 4y2
factorise: a2 − 3a − 40
factorise: 2a2 + 7a + 6
factorise: 4c2 + 3c - 10
factorise: a2 - 23a + 42
factorise: x2y2 - 3xy - 40
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
