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प्रश्न
Factorise the following:
5a2 – 10a – 15
बेरीज
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उत्तर
To factorise 5a2 – 10a – 15, we start by factoring out the greatest common factor (GCF) of the terms.
The GCF of 5a2 – 10a and –15 is 5.
So, factor out 5 from the expression 5(a2 – 2a – 3)
Now, we need to factor a2 – 2a – 3.
We are looking for two numbers that multiply to –3 and add up to –2.
These numbers are –3 and 1, because –3 × 1 = –3 and –3 + 1 = –2.
So, we can rewrite a2 – 2a – 3 as (a – 3)(a + 1)
Thus, the fully factorized form of 5a2 – 10a – 15 is 5(a – 3)(a + 1)
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