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प्रश्न
Factorise the following:
`3sqrt(2)x^2 - 11x + 4sqrt(2)`
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उत्तर
We need to factorise:
`3sqrt(2)x^2 - 11x + 4sqrt(2)`
Step 1: Multiply the coefficient of x2 and the constant term
`3sqrt(2) xx 4sqrt(2) = 12 xx 2`
`3sqrt(2) xx 4sqrt(2) = 24`
So we need two numbers whose product = 24 and sum = –11.
Those numbers are –3 and –8. ...(Because –3 × –8 = 24 – 3 and –3 + –8 = –11)
Step 2: Split the middle term
`3sqrt(2)x^2 - 3x - 8x + 4sqrt(2)`
Step 3: Factor by grouping
Group the terms:
`(3sqrt(2)x^2 - 3x) - (8x - 4sqrt(2))`
Factor each group:
`3x(sqrt(2)x - 1) - 4(2x - sqrt(2))`
Write the second bracket in the same form as the first:
`2x - sqrt(2) = sqrt(2)(sqrt(2)x - 1)`
So, `-4(2x - sqrt(2)) = -4sqrt(2)(sqrt(2)x - 1)`
Thus the expression becomes `3x(sqrt(2)x - 1) - 4sqrt(2)(sqrt(2)x - 1)`
Step 4: Factor out the common bracket
`(sqrt(2)x - 1)(3x - 4sqrt(2))`
