Advertisements
Advertisements
प्रश्न
Factorise the following:
25x2 + 16y2 + 4z2 – 40xy + 16yz – 20xz
Advertisements
उत्तर
25x2 + 16y2 + 4z2 – 40xy + 16yz – 20xz
= (–5x)2 + (4y)2 + (2z)2 + 2(–5x)(4y) + 2(4y)(2z) + 2(2z)(–5x) ...[Using identity, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca]
= (–5x + 4y + 2z)2
= (–5x + 4y + 2z)(–5x + 4y + 2z)
APPEARS IN
संबंधित प्रश्न
Write the following cube in expanded form:
(2x + 1)3
Evaluate the following using suitable identity:
(102)3
If `x + 1/x = sqrt5`, find the value of `x^2 + 1/x^2` and `x^4 + 1/x^4`
Simplify `(x^2 + y^2 - z)^2 - (x^2 - y^2 + z^2)^2`
If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c.
If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2.
Find the cube of the following binomials expression :
\[\frac{1}{x} + \frac{y}{3}\]
If 2x+3y = 13 and xy = 6, find the value of 8x3 + 27y3
Evaluate of the following:
463+343
If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a3 − b3 =
If \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]
If a - b = 0.9 and ab = 0.36; find:
(i) a + b
(ii) a2 - b2.
The difference between two positive numbers is 5 and the sum of their squares is 73. Find the product of these numbers.
Use the direct method to evaluate the following products :
(y + 5)(y – 3)
Use the direct method to evaluate :
(x+1) (x−1)
Use the direct method to evaluate :
(xy+4) (xy−4)
Evaluate: 20.8 × 19.2
Simplify by using formula :
`("a" + 2/"a" - 1) ("a" - 2/"a" - 1)`
If `"a" + (1)/"a" = 2`, then show that `"a"^2 + (1)/"a"^2 = "a"^3 + (1)/"a"^3 = "a"^4 + (1)/"a"^4`
