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प्रश्न
Factorise by substituting terms:
5(x + y)2 – 6x – 6y – 8
बेरीज
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उत्तर
Given expression: 5(x + y)2 – 6x – 6y – 8
= 5(x + y)2 – 6(x + y) – 8
We have to find two numbers whose sum is –6 and whose product is –40.
These numbers are –10 and 4.
Now, using middle term factorisation method,
5(x + y)2 – 6(x + y) – 8
= 5(x + y)2 – 10(x + y) + 4(x+ y) – 8
= 5(x + y) [(x + y) – 2] + 4[(x + y) – 2]
= [(x + y) – 2] [5(x + y) + 4]
= (x + y – 2) (5x + 5y + 4)
The factorisation result is (x + y – 2) (5x + 5y + 4).
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