Advertisements
Advertisements
प्रश्न
Factorise : a3 + 2a2 - a - 2
बेरीज
Advertisements
उत्तर
a3 + 2a2 - a - 2
= a2( a + 2 ) - 1( a + 2 )
= ( a2 - 1 )( a + 2 )
= ( a + 1 )( a - 1 )( a + 2 ) [ ∵ a2 - b2 = ( a + b )( a - b )]
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : 25(2a - b)2 - 81b2
Factorise : 3a5 - 108a3
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise:
(a2 − 1) (b2 − 1) + 4ab
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
