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प्रश्न
Factorise:
9(a − 2)2 − 16(a + 2)2
बेरीज
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उत्तर
9(a − 2)2 − 16(a + 2)2
= 3(a − 2)2 − [4(a + 2)]2
= [3(a − 2) + 4(a + 2)][3(a − 2) − 4(a + 2)] ...[∵ a2 − b2 = (a + b)(a − b)]
= [3a − 6 + 4a + 8] [3a − 6 − 4a − 8]
= (7a + 2)(−a − 14)
= −(7a + 2)(a + 14)
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Method of Factorisation : Difference of Two Squares
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