Advertisements
Advertisements
प्रश्न
Factorise.
25a2 − 4b2 + 28bc − 49c2
बेरीज
Advertisements
उत्तर
25a2 − 4b2 + 28bc − 49c2
= 25a2 − (4b2 − 28bc + 49c2)
= (5a)2 − [(2b)2 − 2 × 2b × 7c + (7c)2]
= (5a)2 − [(2b − 7c)2]
[Using identity (a − b)2 = a2 − 2ab + b2]
= [5a + (2b − 7c)] [5a − (2b − 7c)]
[Using identity a2 − b2 = (a − b) (a + b)]
= (5a + 2b − 7c) (5a − 2b + 7c)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Factorisation - EXERCISE 12.2 [पृष्ठ १५१]
APPEARS IN
संबंधित प्रश्न
Factorise the following expression.
25m2 + 30m + 9
Factorise the following expression.
49y2 + 84yz + 36z2
Factorise the following expression.
4x2 − 8x + 4
Factorise the expression.
7p2 + 21q2
Factorise the expression.
10ab + 4a + 5b + 2
Factorise.
x4 − (y + z)4
Factorise.
a4 − 2a2b2 + b4
Factorise the given expression.
q2 − 10q + 21
Factorise 4y2 – 12y + 9
Factorise a2 – 2ab + b2 – c2.
