Advertisements
Advertisements
प्रश्न
Factorise.
25a2 − 4b2 + 28bc − 49c2
बेरीज
Advertisements
उत्तर
25a2 − 4b2 + 28bc − 49c2
= 25a2 − (4b2 − 28bc + 49c2)
= (5a)2 − [(2b)2 − 2 × 2b × 7c + (7c)2]
= (5a)2 − [(2b − 7c)2]
[Using identity (a − b)2 = a2 − 2ab + b2]
= [5a + (2b − 7c)] [5a − (2b − 7c)]
[Using identity a2 − b2 = (a − b) (a + b)]
= (5a + 2b − 7c) (5a − 2b + 7c)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Factorise the following expression.
a2 + 8a + 16
Factorise the following expression.
49y2 + 84yz + 36z2
Factorise the following expression.
4x2 − 8x + 4
Factorise.
63a2 − 112b2
Factorise the expression.
2x3 + 2xy2 + 2xz2
Factorise the expression.
(lm + l) + m + 1
Factorise the expression.
5y2 − 20y − 8z + 2yz
Factorise the expression.
6xy − 4y + 6 − 9x
Factorise the given expression.
q2 − 10q + 21
Factorise the following by taking out the common factor
3y3 – 48y
