Question

\[f\left( x \right) = \begin{cases}3x - 2, & x < 0; \\ 1, & x = 0; \\ 4x + 1, & x > 0 .\end{cases}\]

find: f(1), f(−1), f(0) and f(2).

 

 

Answer 1

f (1) = 4 × 1 + 1 = 5          [By using f (x) = 4x + 1, x > 0]
f ( -1) = 3 × (-1) -2          [By using f (x) = 3x -2, x < 0]
        = -3-2=-5f (0) = 1             [By using f (x) = 1, x = 0]
f (2) = 4 × 2 + 1                 [By using f (x) = 4x + 1, x > 0]
        = 9
Hence,
f (1) = 5, f (- 1) = -5, f (0) = 1 and f (2) = 9.