मराठी

Express sin 65° + tan 57° in terms of trigonometric ratios of angles between 0° and 45°. - Mathematics

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प्रश्न

Express sin 65° + tan 57° in terms of trigonometric ratios of angles between 0° and 45°.

बेरीज
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उत्तर

Given: Express sin 65° + tan 57°.

Step-wise calculation:

sin 65° = sin (90° – 25°)

= cos 25°

tan 57° = tan (90° – 33°) 

= cot 33°

= `1/ (tan 33^circ)`

= `(cos 33^circ)/(sin 33^circ)`

sin 65° + tan 57° = cos 25° + cot 33°

= `cos 25^circ + 1/(tan 33^circ)` 

= `cos 25^circ + (cos 33^circ)/(sin 33^circ)`, where the angles 25° and 33° lie between 0° and 45°.

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पाठ 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18C [पृष्ठ ३८०]

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नूतन Mathematics [English] Class 9 ICSE
पाठ 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18C | Q 11. | पृष्ठ ३८०
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