Advertisements
Advertisements
प्रश्न
Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°
sec 76° + cosec 52°
Advertisements
उत्तर
We know that `sec(90^@ - theta) = cosec theta` and `cosec (90^@) = sin theta` So
`sec 76^@ + cosec 52^@ = sec(90^@ - 14^@) + cosec (90^@ - 38^@)`
`= cosec14^@ + sec 38^@`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
