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प्रश्न
Express cos A and tan A in terms of sin A.
बेरीज
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उत्तर
To express cos A in terms of sin A:
From the identity sin2 A + cos2 A = 1:
cos2 A = 1 – sin2 A
Taking the square root (assuming A is an acute angle):
`cos A = sqrt(1 - sin^2 A)`
Now, to express tan A in terms of sin A:
We know `tan A = sin A/cos A`
Substitute the expression for cos A derived above:
`tan A = sin A/sqrt(1 - sin^2 A)`
`cos A = sqrt(1 - sin^2 A)` and `tan A = sin A/sqrt(1 - sin^2 A)`
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