Expand : ( X + 8 ) ( X + 10 )

Expand : ( x + 8 ) ( x + 10 )

बेरीज

( x + 8 )( x + 10 ) = x² + ( 8 + 10 )x + 8 x 10
= x² + 18x + 80

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Expansion of Formula

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पाठ 4: Expansions - Exercise 4 (C) [पृष्ठ ६२]

पाठ 4 Expansions
Exercise 4 (C) | Q 1.1 | पृष्ठ ६२

Expand: `( 2x - 1/x )( 3x + 2/x )`

If a + b + c = p and ab + bc + ca = q ; find a² + b² + c².

If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`

In the expansion of (2x² - 8) (x - 4)²; find the value of constant term.

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If a² + b² = 34 and ab = 12; find : 3(a + b)² + 5(a - b)²

If x² + `x^(1/2)`= 7 and x ≠ 0; find the value of:
7x³ + 8x − `7/x^3 - 8/x`

Find the value of 'a': 4x² + ax + 9 = (2x - 3)²

Find the value of 'a': 9x² + (7a - 5)x + 25 = (3x + 5)²