Evaluate: X(X – 5) + 2 for X = 1.

Evaluate: x(x – 5) + 2 for x = 1.

बेरीज

For x = 1

x(x – 5) + 2

1(1 − 5) + 2

−4 + 2

= −2

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Multiplying a Polynomial by a Polynomial

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पाठ 11: Algebraic Expressions - Exercise 11 (C) [पृष्ठ १४३]

पाठ 11 Algebraic Expressions
Exercise 11 (C) | Q 12.1 | पृष्ठ १४३

Multiply: 2y − 4y³ + 6y⁵ by y² + y − 3

Multiply:

5p²+ 25pq + 4q² by 2p² − 2pq +3q²

Simplify: (5a + 5b – c) (2b – 3c)

The adjacent sides of a rectangle are x² – 4xy + 7y² and x³ – 5xy². Find its area.

The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.

Multiply -4xy³ and 6x²y and verify your result for x = 2 and y= 1.

Find the value of (3x³) × (-5xy²) × (2x²yz³) for x = 1, y = 2 and z = 3.

If x = 2 and y = 1; find the value of (−4x²y³) × (−5x²y⁵).

Evaluate: xz (x² + y²) for x = 2, y = 1 and z= 1.

Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.