Advertisements
Advertisements
प्रश्न
Evaluate the following definite integrals:
`int_3^4 (d"x)/(x^2 - 4)`
बेरीज
Advertisements
उत्तर
Let I = `int_3^4 (d"x)/(x^2 - 4)`
= `int_3^4 ("d"x)/(x^2 - 2^2)` ......`[because ("d"x)/(x^2 - 2^2) = 1/(2"a") log((x - "a")/(x "a"))]`
= `[1/(2(2)) log((x - 2)/(x + 2))]_3^4`
= `1/4[log(2/6) - log(1/5)]`
= `1/4[log(2/6 xx 5/1)]`
= `1/4 log (5/3)`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
