Advertisements
Advertisements
प्रश्न
Evaluate the following:
`(cot 40^circ)/(tan 50^circ) - 1/2(cos 35^circ/sin 55^circ)`
मूल्यांकन
Advertisements
उत्तर
Given: `(cot 40°)/(tan 50°) - 1/2 (cos 35^circ/sin 55^circ)`
Step-wise calculation:
1. Use complementary-angle identities: cot θ = tan(90° – θ) and sin(90° – θ) = cos θ.
Hence cot 40° = tan 50° and sin 55° = cos 35°.
2. Substitute: `(cot 40^circ)/(tan 50^circ) = (tan 50^circ)/(tan 50^circ) = 1`.
3. And `(cos 35^circ)/(sin 55^circ) = (cos 35^circ)/(cos 35^circ) = 1`
So `(1/2)(cos 35^circ/sin 55^circ) = 1/2`.
4. Therefore the whole expression = `1 - 1/2 = 1/2`.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Trigonometric Ratios - EXERCISE 10.3 [पृष्ठ १०.३६]
