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प्रश्न
Evaluate \[\int \frac{dx}{x^2-a^2}\].
पर्याय
\[\sin^{-1}\left(\frac{x}{a}\right)+C\]
\[\frac{1}{2a}\log\left|\frac{x-a}{x+a}\right|+C\]
\[\frac{1}{2a}\log\left|\frac{a+x}{a-x}\right|+C\]
\[\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)+C\]
MCQ
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उत्तर
The denominator has the standard form \[x^2-a^2\]. Its integral is a logarithmic expression with the ratio \[\frac{x-a}{x+a}\].
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