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प्रश्न
Evaluate: `((-4)/5 xx 3/2) + (9/-5 xx 10/3) - ((-3)/2 xx (-1)/4)`
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उत्तर १
`((-4)/5 xx 3/2) + (9/-5 xx 10/3) - ((-3)/2 xx (-1)/4)`
`= ((-2 xx 3)/(5 xx 1)) + ((3 xx 2)/(-1 xx 1)) - ((- 3 xx (- 1))/(2 xx 4))`
`= ((-6)/5) + ((-6)/1) - (3/8)`
`= (- 6 xx 8)/(5 xx 8) - (6 xx 40)/(1 xx 40) - (3 xx 5)/(8 xx 5)`
`= (- 48 - 240 - 15)/40`
`= (- 288 - 15)/40`
`= (-303)/40`
उत्तर २
`((-4)/5 xx 3/2) + (9/-5 xx 10/3) - ((-3)/2 xx (-1)/4)`
Simplify each product
`(-4)/5 xx 3/2 = (-4xx3)/(5xx2) = (-12)/10 = (-6)/5`
`9/-5xx10/3 = (9xx10)/(-5xx3) = 90/-15 = -6/1 = -6`
`(-3)/2xx(-1)/4 = (-3xx-1)/(2xx4) = 3/8`
The expression becomes: `(-6)/5+(-6)-3/8`
The denominators are 5, 1, and 8. The least common denominator (LCD) is 40. Rewrite each term with a denominator of 40:
1. `(-6)/5=(-48)/40`
2. `-6 = (-240)/40`
3. `(-3)/8 = (-15)/40`
`(-48)/40+(-240)/40-15/40`
`= (-48-240-15)/40`
`= (-303)/40`
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