मराठी

Evaluate: (√3 + √52)^1/2 ⁢(√52 − √3)^1/2 - Mathematics

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प्रश्न

Evaluate:

`(sqrt(3) + sqrt(52))^(1/2) (sqrt(52) - sqrt(3))^(1/2)`

मूल्यांकन
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उत्तर

Given,

`(sqrt(3) + sqrt(52))^(1/2) (sqrt(52) - sqrt(3))^(1/2)`

We have to evaluate the given terms.

Thus, `(sqrt(3) + sqrt(52))^(1/2) (sqrt(52) - sqrt(3))^(1/2)`

⇒ `(sqrt(52) + sqrt(3))^(1/2) (sqrt(52) - sqrt(3))^(1/2)`  ...[∴ a + b = b + a]

⇒ `[(sqrt(52) + sqrt(3))(sqrt(52) - sqrt(3))]^(1/2)`  ...[∴ an × bn = (ab)n]

⇒ `[(sqrt(52))^2 - (sqrt(3))^2]^(1/2)`  ...[∴ (a + b)(a – b) = a2 – b2]

⇒ `[52 - 3]^(1/2)`

⇒ `[49]^(1/2)`

⇒ `[7^2]^(1/2) = (7)^(2 xx 1/2)`

⇒ 7

Hence, `(sqrt(3) + sqrt(52))^(1/2) (sqrt(52) - sqrt(3))^(1/2) = 7`

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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६६]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 6 Indices
EXERCISE 6 | Q 4. (ii) | पृष्ठ ६६
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