मराठी

Evaluate: (25/4)^−1/2 − (1/27)^1/3 + 7^0 - Mathematics

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प्रश्न

Evaluate:

`(25/4)^((-1)/2) - (1/27)^(1/3) + 7^0`

मूल्यांकन
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उत्तर

Let’s evaluate:

`(25/4)^(-1/2) - (1/27)^(1/3) + 7^0`

Step 1: Evaluate each part

1. `(25/4)^(-1/2)`

  • `(25/4)^(1/2) = sqrt(25)/sqrt(4) = 5/2`
  • Then apply negative exponent:
    `(25/4)^(-1/2) = 1/(5/2) = 2/5`

2. `(1/27)^(1/3) = 1/root(3)(27) = 1/3`

3. 70 = 1

Step 2: Combine all parts

`2/5 - 1/3 + 1`

Find a common denominator for fractions:

`2/5 = 6/15`

`1/3 = 5/15`

`6/15 - 5/15 + 1`

= `1/15 + 1`

= `1 1/15`

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पाठ 6: Indices - MISCELLANEOUS EXERCISE [पृष्ठ ६९]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 6 Indices
MISCELLANEOUS EXERCISE | Q 4. (iv) | पृष्ठ ६९
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